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- 这篇文章介绍了当WordPress开启错误记录以后,根据error_log来发现SQL注入攻击的思路。
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$ W8 x8 i- K% J9 Z吸引Cocoa的是这个博客其实是TrustWave公司下属的一个叫Spiderlab团队的官方博客,貌似比较有意思。例如它提到了Honeypot Alert这个标签里的文章都是分析他们一个Web蜜罐的Apache access_log日志的。( [& Q; a6 A0 @- J
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简单介绍一下这篇文章吧。
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7 t0 @9 W* ?- s# H# c. T开启WP错误记录功能
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" R( m! z3 N9 ?0 d, ^@ini_set('log_errors','On'); @ini_set('display_errors','Off'); @ini_set('error_log','/home/example.com/logs/php_error.log');SQL 注入扫描
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[07-Dec-2012 02:40:49] WordPress database error You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'WHERE id = -1\'' at line 1 for query SELECT text, author_id, date FROM WHERE id = -1\' y3 h. c" s8 f, X$ O, v# Q, D5 k
[07-Dec-2012 02:40:50] WordPress database error You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'WHERE id = 999999.9 UNION ALL SELECT 0x31303235343830303536--' at line 1 for query SELECT text, author_id, date FROM WHERE id = 999999.9 UNION ALL SELECT 0x31303235343830303536--; b/ b- ]& ] ~' W" N: w$ p' s
[07-Dec-2012 02:40:53] WordPress database error You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'WHERE id = 999999.9 UNION ALL SELECT 0x31303235343830303536,0x313032353438303035' at line 1 for query SELECT text, author_id, date FROM WHERE id = 999999.9 UNION ALL SELECT 0x31303235343830303536,0x31303235343830303536--
+ `: k4 H0 h6 w0 N! {# I上面的日志就是在暴力猜解表的列数,那个巨大的十六进制值会被解析成null。
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攻击者使用了类似"waitfor delay"和"benchmark"这样的函数来盲注。 }1 V# E! i5 u# k1 X1 o: Y
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[07-Dec-2012 02:43:21] WordPress database error You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'WHERE id = -1; if (1=1) waitfor delay \'00:00:05\'--' at line 1 for query SELECT text, author_id, date FROM WHERE id = -1; if (1=1) waitfor delay \'00:00:05\'--& p3 o! P' M2 O2 b, c0 U
[07-Dec-2012 02:43:27] WordPress database error You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'WHERE id = -1 and if(1=1,BENCHMARK(8623333,MD5(0x41)),0)' at line 1 for query SELECT text, author_id, date FROM WHERE id = -1 and if(1=1,BENCHMARK(8623333,MD5(0x41)),0)
4 e- ]5 _1 L; b# n/ DGoogle一下大规模扫描
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僵尸网络控制着可能使用被感染主机来识别潜在的目标。下面是该公司的蜜罐捕获到的一个RFI(远程文件包含)攻击代码里的片段: - sub google() { my @list; my $key = $_[0]; for (my $i=0; $i<=400; $i+=10){ my $search = ("http://www.google.com/search?q=".&key($key)."&num=100&filter=0&start=".$i); my $res = &search_engine_query($search); while ($res =~ m/<a href="\"?http:\/\/([^">\"]*)\//g) { if ($1 !~ /google/){ my $link = $1; my @grep = &links($link); push(@list,@grep); } } } return @list;
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0 S. Q: R7 g2 a; LCocoa总结:文章比较简单,但是从日志来检测攻击貌似是目前流行的一个方向。 a( v5 `: E; R
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