从WordPress错误日志里发现SQL注入扫描攻击

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• 这篇文章介绍了当WordPress开启错误记录以后，根据error_log来发现SQL注入攻击的思路。
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  " u9 I! X1 @7 q吸引Cocoa的是这个博客其实是TrustWave公司下属的一个叫Spiderlab团队的官方博客，貌似比较有意思。例如它提到了Honeypot Alert这个标签里的文章都是分析他们一个Web蜜罐的Apache access_log日志的。
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  简单介绍一下这篇文章吧。
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  开启WP错误记录功能
  只需要修改wp-config.php的如下几行：
  
  4 ?1 D" \" \; C@ini_set('log_errors','On'); @ini_set('display_errors','Off'); @ini_set('error_log','/home/example.com/logs/php_error.log');SQL 注入扫描
  
  # m& Q* G1 J# ~/ k[07-Dec-2012 02:40:49] WordPress database error You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'WHERE id = -1\'' at line 1 for query SELECT text, author_id, date FROM  WHERE id = -1\'
  [07-Dec-2012 02:40:50] WordPress database error You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'WHERE id = 999999.9 UNION ALL SELECT 0x31303235343830303536--' at line 1 for query SELECT text, author_id, date FROM  WHERE id = 999999.9 UNION ALL SELECT 0x31303235343830303536--
  - l- C+ F! O: c( ~# h! F[07-Dec-2012 02:40:53] WordPress database error You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'WHERE id = 999999.9 UNION ALL SELECT 0x31303235343830303536,0x313032353438303035' at line 1 for query SELECT text, author_id, date FROM  WHERE id = 999999.9 UNION ALL SELECT 0x31303235343830303536,0x31303235343830303536--
  上面的日志就是在暴力猜解表的列数，那个巨大的十六进制值会被解析成null。
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    v3 T* o6 f3 H0 m, B  g攻击者使用了类似"waitfor delay"和"benchmark"这样的函数来盲注。
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  [07-Dec-2012 02:43:21] WordPress database error You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'WHERE id = -1; if (1=1) waitfor delay \'00:00:05\'--' at line 1 for query SELECT text, author_id, date FROM  WHERE id = -1; if (1=1) waitfor delay \'00:00:05\'--
  ! t! q# a9 ]/ ~) l+ y& I: T5 J; U[07-Dec-2012 02:43:27] WordPress database error You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'WHERE id = -1 and if(1=1,BENCHMARK(8623333,MD5(0x41)),0)' at line 1 for query SELECT text, author_id, date FROM  WHERE id = -1 and if(1=1,BENCHMARK(8623333,MD5(0x41)),0)
  - H" z. N6 H& PGoogle一下大规模扫描
  
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  ; S! ^! d0 a3 a                               僵尸网络控制着可能使用被感染主机来识别潜在的目标。下面是该公司的蜜罐捕获到的一个RFI（远程文件包含）攻击代码里的片段：
• sub google() { my @list; my $key = $_[0]; for (my $i=0; $i<=400; $i+=10){ my $search = ("http://www.google.com/search?q=".&key($key)."&num=100&filter=0&start=".$i); my $res = &search_engine_query($search); while ($res =~ m/<a href="\"?http:\/\/([^">\"]*)\//g) { if ($1 !~ /google/){ my $link = $1; my @grep = &links($link); push(@list,@grep);            }        }    } return @list；
  

Cocoa总结：文章比较简单，但是从日志来检测攻击貌似是目前流行的一个方向。​